Where and why do I have to put the "template" and "typename" keywords?

Answer

In order to parse a C++ program, the compiler needs to know for certain names whether they are types or not. The following example demonstrates that

t * f;

How should this be parsed? For many languages a compiler doesn't need to know the meaning of a name in order to parse and basically know what action a line of code does. In C++, the above however can yield vastly different interpretations depending on what t means. If it's a type, then it will be a declaration of a pointer f. However if it's not a type, it will be a multiplication. So the C++ Standard says at paragraph 3p7

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